Two masses m 1 and m 2 are connected by a spring of spring constant k and are placed on a smooth horizontal surface. Initially the spring is stretched through a distance 'd' when the system is released from rest. Find the distance moved by the two masses when spring is compressed by a distance 'd'.
Text Solution
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, 
Sol.
Energy Conservation
⇒ Total change in length of spring = 2x { ∴ 
= 
}
Time is same
no external force ∴ centre of mass is at rest
hence m 1 x 1 = m 2 x 2 ⇒ 
= 
& x 1 + x 2 = 2d
or, m 1 x 1 = m 2 x 2 & x 1 + x 2 = 2d
x 1 = 
⇒ 
+ x 2 = 2d
x 2 
= 2d ⇒ x 2 
= 2d
x 2 = 
& x 1 = 
Ans.
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